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The molar conducatance of Ba^(2+) and Cl...

The molar conducatance of `Ba^(2+)` and `Cl^(-)` are `127` and `76 ohm^(-1) cm^(-1) mol^(-1)` respectively at infinite dilution. The equivalent conductance of `BaCl_(2)` at infinte dilution will be

A

330

B

203

C

139.5

D

51

Text Solution

Verified by Experts

The correct Answer is:
C
`^^^_(m)^(oo)" for " BaCl_2 = ^^^_(m)^(oo)Ba^(2+)+2^^^_(m)^(oo)Cl^(-)`
`:. ^^^_(eq)^(oo)" for " BaCl_2 =1/2 ^^^_(m)^(oo)Ba^(2+)+^^^_(m)^(oo)Cl^(-)`
`=1/2 xx127 + 76`
`=13.9 5 Omega ^(-1)cm^2`
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Knowledge Check

  • The equivalent conductance of Ba^(2+) and Cl^(c-) are 63.5ohm^(-1) cm^(2) eq^(-1) and 76 ohm^(-1) cm^(2)eq^(-1) , respectively, at infinite dilution . The equivalent conductance ( in oh^(-1) cm^(2)) of BaCl_(2) at infinite dilution will be

    A
    `139.5`
    B
    `203.0`
    C
    `279.0`
    D
    `101.15`

  • At inifnite dilution equivalent conductances of Ba^(+2) & CI^(-) ions are 127 & 76 "ohm^(-1) cm^(-1) eq^(-1) respectively. Equivalent conductance of BaCI_(2) at infinate dilutions is:

    A
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  • The ionic conductance of Ba^(2+) and CI^(-) are respectively 127 and 76 omega^(-1) cm^(2) of BaCI_(2) at infinite dilution will be

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