The molar conducatance of `Ba^(2+)` and `Cl^(-)` are `127` and `76 ohm^(-1) cm^(-1) mol^(-1)` respectively at infinite dilution. The equivalent conductance of `BaCl_(2)` at infinte dilution will be

Options

A. 330
B. 203
C. 139.5
D. 51

Answer

C

Explanation

`^^^_(m)^(oo)" for " BaCl_2 = ^^^_(m)^(oo)Ba^(2+)+2^^^_(m)^(oo)Cl^(-)`
`:. ^^^_(eq)^(oo)" for " BaCl_2 =1/2 ^^^_(m)^(oo)Ba^(2+)+^^^_(m)^(oo)Cl^(-)`
`=1/2 xx127 + 76`
`=13.9 5 Omega ^(-1)cm^2`