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Specific conductance of 0.1 MHA is 3.75x...

Specific conductance of 0.1 MHA is `3.75xx10^(-4)ohm^(-1)cm^(-1)`. If `lamda^(oo)` of HA is `250 ohm^(-1)cm^2mol^(-1)`, then dissociation constant `K_a` of HA is

A

`1. 0 xx 10 ^(-5)`

B

`2.25 xx 10 ^(-4)`

C

`2.25 xx 10 ^(-5)`

D

`2.25 xx 10 ^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

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