Home
Class 12
PHYSICS
Show that the electric field at the surf...

Show that the electric field at the surface of a charged conductor is given bu`vecE = sigma/epsilon_0 hatn`, where `sigma` is the surface charge density and `hatn` is a unit vector normal to the surface in the outward direction.

Answer

Step by step text solution for Show that the electric field at the surface of a charged conductor is given buvecE = sigma/epsilon_0 hatn, where sigma is the surface charge density and hatn is a unit vector normal to the surface in the outward direction. by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GAUSS' THEOREM

    MODERN PUBLICATION|Exercise EXERCISE|95 Videos

  • FORCE ON A CURRENT

    MODERN PUBLICATION|Exercise EXERCISE|105 Videos

  • Huygen's Principle

    MODERN PUBLICATION|Exercise EXERCISE|45 Videos

Similar Questions

Explore conceptually related problems

What is the value of electric field intensity at the surface of charged conductor ?

What is the SI unit of surface charge density ?

Knowledge Check

  • If the surface charge density of charge be sigma , electric field near the surface would be:

    A
    `(2sigma)/varepsilon_(0)`
    B
    `sigma/varepsilon_(0)`
    C
    `sigma/(2varepsilon_(0))`
    D
    `(3sigma)/(2varepsilon_(0))`

    • Similar Questions

    Explore conceptually related problems

    Show that the potential is constant within and at the surface of a charged conductor.

    Show that charge always resides on the outer surface of a conductor.

    Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_2 - E_1) hatn= (sigma)/(epsilon_0) where hatn is a unit vector normal to the surface at a point and is the surface charge density at that point. (The direction of hat n is from side 1 to side 2.) Hence show that just outside a conductor, the electric field is sigma hatn // epsilon_0

    Show that total electric flux over a closed surface due to charge outside the surface is zero?

    Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_2 - E_1) hatn= (sigma)/(epsilon_0) where n is a unit vector normal to the surface at a point and is the surface charge density at that point. (The direction of hatn is from side 1 to side 2.) Hence show that just outside a conductor, the electric field is sigma hatn // epsilon_0 . Show that the tangential component of electrostatic field is continuous from one side of a charged surface to another.

    Show that electric field everywhere is normal to the equipotential surface .

    Show that electric field everywhere is normal to the equipotential surface.

    Home
    Profile