The isotope Manganese-56 decays and udergoes beta- particle eission to form the stable isotope Iron-56 .The half life for this decay is 2.6 hours .Initially,at time t=0,a sample of Manganese-56 has a mass of 1.4muG and there is no iron - 56. For the smple of Manganese-56 ,determine the initial number of Manganese-56 atoms in the sample an d

The isotope Manganese-56 decays and udergoes beta- particle eission to form the stable isotope Iron-56 .The half life for this decay is 2.6 hours .Initially,at time t=0,a sample of Manganese-56 has a mass of 1.4muG and there is no iron - 56. Determine the time at which the ratio is equal to 9.0.

The isotope Phosphorus-33 undergoes beta - decay to form Sulphur-33, which is stable.The half - life of Phosphorus-33 is 24.8 days. Show that the decay constant of Phosphorus -33 is 3.23 xx 10^(-7) s^(-1) .

The isotope Phosphorus-33 undergoes beta - decay to form Sulphur-33,which is stable.The half - life of Phosphorus-33 is 24.8 days. A pure sample of Phosphorus - 33 has an initial activity of 3.7 xx 10^6 Bq. Calculate the initial number of Phosphorus - 33 nuclei in the sample,

Strontium-90 is a radioactive isotope having a half-life of 28 years.Strontium-90 has a denstiy f 2.5 g cm^(-3) .A smaple of Strontium-90 has an activity of 6.4 xx 10^9 Bq .Calculate the mass of stronitium 90 in the sample

Strontium-90 is a radioactive isotope having a half-life of 28 years.Strontium-90 has a denstiy f 2.5 g cm^(-3) .A smaple of Strontium-90 has an activity of 6.4 xx 10^9 Bq .Calculate the volume of the sample.

The isotope Phosphorus-33 (_(15)P^(33)) undergoes beta - decay to form "Sulphur"-33(_(16)S^(33)) ,which is stable.The half - life of Phosphorus-33 is 24.8 days. A pure sample of Phosphorus - 33 has an initial activity of 3.7 xx 10^6 Bq.Calculate the number of Phophorus - 33 nuclei remaining in the sample after 30 days.

Strontium-90 decays with the emission of a beta- particle to form Ytrium-90 .The reaction is represented by the equation _(38)Sr^(90) rarr _(39)Y^(90) + _(-1)e^0 + 0.55 MeV the decay constant is 0.025 year ^(-1) . At the time of purchase of a Stronituim-90 source the activity is 3.7 xx 10^6 Bq . Calculate ,for this sample of strontium,the initial number of atoms.

Radioactive disintegration is a first order reaction and its rate depends only upon the nature of nucleus and does not depend upon external factors like temperature and pressure. The rate of radioactive disintegration (Activity) is represented as -(dN)/(dt)=lambdaN Where lambda= decay constant, N= number of nuclei at time t, N_(0) =initial no. of nuclei. The above equation after integration can be represented as lambda=(2.303)/(t)log((N_(0))/(N)) Half-life period of U is 2.5xx10^(5) years. In how much time will the amount of U^(237) remaining be only 25% of the original amount ? a) 2.5xx10^(5) year b) 1.25xx10^(5) years c) 5xx10^(5) years d) none of these

The integrated rate equations can be fitted with kinetic data to determine the order of a reaction. The integrated rate equations for zero, first and second order reactions are : Zero order : [Al =-kt+ [A]_0 First order : log [A] = -(kt)/2.303 + log [A]_0 Second order : 1/([A])=kt+1/[A]_0 These equations can also be used to calculate the halt life periods of different reactions, which give the time during which the concentration of a reactant is reduced to half of its initial concentration, i.e, at time t_(1//2), [A] = [A]_0//2 Answer the following (1 to 5) question : The decomposition of nitrogen pentoxide : 2N_2O_5(g) rarr 4NO_2(g) + O_2(g) is a first order reaction. The plot of log [N_2O_5] vs time (min) has slope = - 0.01389. The rate constant k is