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Assertion : [Ni(CO)4] is diamagnetic and...

Assertion : `[Ni(CO)_4]` is diamagnetic and tetrahedral in shape. Reason : `[Ni(CO)_4]` contains no unpaired electron and involves `dsp^2` hybridisation.

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[Ni(CN)_4]^(2-) is diamagnetic and has ............. shape.

The number of unpaired electrons in Ni^(2+) is

Knowledge Check

  • The number of unpaired electrons in Ni^(2+)

    A
    Zero
    B
    2
    C
    4
    D
    8

  • The no of unpaired electrons in Co^(+2) are

    A
    0
    B
    2
    C
    3
    D
    7

  • The number of unpaired electron in [Ni(CO)_2] is

    A
    0
    B
    1
    C
    3
    D
    4

    • Similar Questions

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    Explain the geometry of [Ni (CO)_4] on basis of VBT.

    Assertion : ([Fe(CN)_6]^(3-) ion shows magnetic moment corresponding to two unpaired electrons. Reason : Because it has d^2sp^3 type hybridisation

    Explain, Why [Ni(CO)_4] is diamagnetic whereas [NiCl_4]^(2-) is paramagnetic ?

    The number of unpaired electrons in Ni^(2+) is :

    How many unparied electrons are present in a Co^(2+) complex having dsp^(2) hybriodization ?

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