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If the energy of a hydrogen atom in n^(t...

If the energy of a hydrogen atom in `n^(th)` orbit is `E_n` then energy in the nth orbit of a singly ionized helium atom will

A

`4E_n`

B

`E_n/4`

C

`2E_n`

D

`E_n//2`

Text Solution

Verified by Experts

The correct Answer is:
A

`E_nprop Z^2 :. (E_(He^(+)))/(E_H)=((2)^2)/((1)^2)=4`
`E_(He^(+))= 4E_H=4E_n " "(E_H=E_n)`
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Knowledge Check

  • Energy of hydrogen atom in the second exited state is

    A
    miinus 3.4 eV
    B
    minus 1.51 eV
    C
    1.51 eV
    D
    3.4 eV
  • In the Bohr model of a hydrogen atom, the ratio of the kinetic energy to the total energy of the electron is

    A
    `-1`
    B
    `-2`
    C
    `+1`
    D
    `+1/2`
  • The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å . The wavelength of the second spectral line in the Balmer series in single-ionized helium atom is:

    A
    `1215 Å`
    B
    `1640Å`
    C
    `2430Å`
    D
    `4687Å`
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