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The mass of glucose that should be disso...

The mass of glucose that should be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1g of urea in the same quantity of water is

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The correct Answer is:
3
`(Delta p)_("glucose") = (Delta p)_("urea") and (x_(B))_("glucose") = (x_(B))_("urea")`
`because` amoutn of water is the same `(n_(B))` urea = `(n_(B))` glucose
i.e, `((n_(B))/(n_(A)))_("glucose") = ((n_(B))/(n_(A)))_("urea") or (w-(B))/(50) xx (18)/(180) = (1 xx 18)/(50 xx 60), w_(B)= 3g`
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