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The mass of glucose that should be disso...

The mass of glucose that should be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1g of urea in the same quantity of water is

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The correct Answer is:
3
`(Delta p)_("glucose") = (Delta p)_("urea") and (x_(B))_("glucose") = (x_(B))_("urea")`
`because` amoutn of water is the same `(n_(B))` urea = `(n_(B))` glucose
i.e, `((n_(B))/(n_(A)))_("glucose") = ((n_(B))/(n_(A)))_("urea") or (w-(B))/(50) xx (18)/(180) = (1 xx 18)/(50 xx 60), w_(B)= 3g`
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Knowledge Check

  • What mass of solute ("molar mass=60 g mol"^(-1)) should be dissolved in 180 g water to reduce the vapour pressure to 4/5 th of pure water :

    A
    120g
    B
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    C
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    D
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    B
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    Neutral solution
    D
    Cannot be predicted

  • Sodium hydride (NaH) when dissolved in water, produces

    A
    Acidic solution
    B
    Basic solution
    C
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    D
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