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A certain sum amounts to ₹11760 in 2(1)/...

A certain sum amounts to ₹11760 in `2(1)/(2)` years at 9% p.a. simple interest. What will be the simple interest on the same sum for `4(2)/(5)` years at 15% p.a?

A

₹6336

B

₹6363

C

₹6436

D

₹6433

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the principal amount first and then calculate the simple interest for the new time period and rate. ### Step 1: Understand the given information We know that the amount (A) after a certain time (T) at a certain rate (R) can be calculated using the formula: \[ A = P + SI \] Where: - \( A \) = Final amount (₹11760) - \( P \) = Principal amount - \( SI \) = Simple Interest ### Step 2: Calculate the Simple Interest for the first scenario The formula for Simple Interest (SI) is: \[ SI = \frac{P \times R \times T}{100} \] Given: - \( R = 9\% \) - \( T = 2.5 \) years (which is \( \frac{5}{2} \)) We can rewrite the total amount as: \[ A = P + SI \] So, \[ 11760 = P + \frac{P \times 9 \times 2.5}{100} \] ### Step 3: Substitute and simplify Substituting the values into the equation gives: \[ 11760 = P + \frac{P \times 22.5}{100} \] \[ 11760 = P + \frac{22.5P}{100} \] \[ 11760 = P \left(1 + \frac{22.5}{100}\right) \] \[ 11760 = P \left(\frac{100 + 22.5}{100}\right) \] \[ 11760 = P \left(\frac{122.5}{100}\right) \] ### Step 4: Solve for the Principal (P) Now, we can solve for \( P \): \[ P = \frac{11760 \times 100}{122.5} \] \[ P = \frac{1176000}{122.5} \] \[ P = 9600 \] ### Step 5: Calculate the Simple Interest for the new scenario Now we need to find the simple interest for the same principal amount at a new rate and time: - New \( R = 15\% \) - New \( T = 4.5 \) years (which is \( \frac{22}{5} \)) Using the SI formula again: \[ SI = \frac{P \times R \times T}{100} \] Substituting the values: \[ SI = \frac{9600 \times 15 \times 4.5}{100} \] ### Step 6: Calculate the Simple Interest \[ SI = \frac{9600 \times 15 \times 4.5}{100} \] \[ SI = \frac{9600 \times 67.5}{100} \] \[ SI = \frac{645000}{100} \] \[ SI = 6450 \] ### Final Answer The simple interest on the same sum for \( 4\frac{2}{5} \) years at 15% p.a. is ₹6450. ---
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Knowledge Check

  • A certain sum amounts to Rs. 9243.20 in 1^(1/2) years at 4% p.a. simple interest. What will be the simple interest on the same sum for 7^(1/2) years at 8% per annum?

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    Rs. 6000
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    Rs. 5000
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  • A sum amounts to Rs 14,395 at 9.25% p.a. simple interest in 5.4 years. What will be the simple interesfon the same sum at 8.6% p.a. in 4.5 years ?

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