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How many two digit numbers are divisible...

How many two digit numbers are divisible by 3 but not by 7?

A

13

B

26

C

30

D

47

Text Solution

AI Generated Solution

The correct Answer is:
To find how many two-digit numbers are divisible by 3 but not by 7, we can follow these steps: ### Step 1: Identify the range of two-digit numbers The two-digit numbers range from 10 to 99. ### Step 2: Find the two-digit numbers divisible by 3 To find the two-digit numbers divisible by 3, we need to identify the smallest and largest two-digit numbers that are divisible by 3. - The smallest two-digit number divisible by 3 is 12 (since 10 and 11 are not divisible by 3). - The largest two-digit number divisible by 3 is 99 (since 99 is divisible by 3). ### Step 3: Use the formula for an arithmetic sequence The two-digit numbers divisible by 3 form an arithmetic sequence where: - First term (a) = 12 - Last term (l) = 99 - Common difference (d) = 3 The number of terms (n) in an arithmetic sequence can be calculated using the formula: \[ n = \frac{l - a}{d} + 1 \] Substituting the values: \[ n = \frac{99 - 12}{3} + 1 \] \[ n = \frac{87}{3} + 1 \] \[ n = 29 + 1 \] \[ n = 30 \] So, there are 30 two-digit numbers that are divisible by 3. ### Step 4: Find the two-digit numbers divisible by both 3 and 7 Next, we need to find the two-digit numbers that are divisible by both 3 and 7. The least common multiple (LCM) of 3 and 7 is 21. - The smallest two-digit number divisible by 21 is 21. - The largest two-digit number divisible by 21 is 84. ### Step 5: Count the two-digit numbers divisible by 21 Using the same arithmetic sequence formula: - First term (a) = 21 - Last term (l) = 84 - Common difference (d) = 21 Calculating the number of terms (n): \[ n = \frac{l - a}{d} + 1 \] \[ n = \frac{84 - 21}{21} + 1 \] \[ n = \frac{63}{21} + 1 \] \[ n = 3 + 1 \] \[ n = 4 \] So, there are 4 two-digit numbers that are divisible by both 3 and 7 (which are 21, 42, 63, and 84). ### Step 6: Calculate the final count To find the two-digit numbers that are divisible by 3 but not by 7, we subtract the count of numbers that are divisible by both 3 and 7 from the count of numbers that are divisible by 3: \[ \text{Total} = 30 - 4 = 26 \] Thus, the final answer is that there are **26 two-digit numbers that are divisible by 3 but not by 7**.
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Knowledge Check

  • How many two digit numbers are divisible by 4 ?

    A
    `q^(2)=pr`
    B
    `r^(2)=pq`
    C
    `pqr=1`
    D
    `2q=p+r`
  • How many two digit numbers are divisible by 4 ?

    A
    21
    B
    22
    C
    24
    D
    25
  • How many three digit numbers are divisible by 6?

    A
    196
    B
    149
    C
    150
    D
    151
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