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Hoffmann bromamide reaction involves con...

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain.
`R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3)`
Mechanism of the reaction is :

Number of moles of NaOH consumed in above reaction.

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
D
`RCONH_(2) +Br_(2)+4NaOH to RNH_(2)`
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Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Product (A) :

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Product (A) is :

Knowledge Check

  • The major product in the reaction, CH_(3)CH_(2)NH_(2)+Cl-overset(O)overset(||)C-CH_(3) is

    A
    N - Methylaminoethane
    B
    Propionamide
    C
    N - Ethylacetamide
    D
    N - Methylacetamide.

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    Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Which of the following will not give Hoffmann bromamide reaction.

    R-overset(O)overset(||)C-NH_(2)+xNaOH +Br_(2) to R-NH_(2)+2NaBr +Na_(2)CO_(3) +H_(2)O Number of moles of NaOH used in above Hoffmann bromamide reaction is :

    H - C = C- H underset(H_2SO_4) overset(HgSO_4)to (A) underset((2) H_3O^(o+)) overset((1) NH_3 + HCN)to(B) , Product (B) of given reaction is :

    CH_(3)CH_(2)C-=CH underset("liq. " NH_(3))overset(NaNH_(2))rarr I Product (K) of the above reaction is :

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    CH_3 - overset(CH_3)overset(|)underset(OH)underset(|)C-CH_3 overset(Na_2Cr_2O_7)underset("cool") rarr (P) , product (P) in the reaction is :

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