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Shows a cylindrical tube with adiabatic walls and fittled with a diathermic separetor. The separetor can be slid in the tube by and external mechanism. An ideal gas is injected into the two sides at equal pressures and equal temperatures. The separetor remaons in equilibrium at the middle. It is now slid to pisition where it devides the tube in the ratio of 1:3. Find the ratio of the pressures in the two parts of the vessel.

Text Solution

Verified by Experts

According to question, tube divided in the
ration 1:3
From the formula PV= nRT
` So (P_2/P_1) = (V_2/V_1) = 1:3`.
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