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A wheel rotates with a constant accelera...

A wheel rotates with a constant acceleration of `2.0(rad)/s^2`. If the wheel starts from rest, how many revolutions will it make in the first 10 seconds?

Text Solution

Verified by Experts

The angular displacement in the first 10 seconds is ginven by
`theta=omega_0t+1/2alphat^2=1/2(2.0rad/s^2)(10s)^=10rad`.
As the whel turns by `2pi` radian in each revolution, the number of revolutions in 10 s is
`n=100/(2pi)=16`
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