Home
Class 12
PHYSICS
The magnetic field at the origin due to ...

The magnetic field at the origin due to a current element I `(vec dl ) placed at a positon (vec r) is`

A

`(((mu_0 i)/(4pi))` `(vec (dl) xx vec (r))/r^3)`

B

`(-((mu_0)i/(4 pi) (vec(r) xx vec(dl) / r^3)))`

C

`((mu_0)i/(4 pi) (vec(r) xx vec(dl) / r^3))`

D

`(-((mu_0)i/(4pi)(vec (dl) xx vec (r))/r^3))`

Text Solution

Verified by Experts

The correct Answer is:
C, D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MAGNETIC FIELD DUE TO CURRENT

    HC VERMA|Exercise exercise|61 Videos

  • MAGNETIC FIELD DUE TO CURRENT

    HC VERMA|Exercise Objective 1|12 Videos

  • MAGNETIC FIELD

    HC VERMA|Exercise Exercises|60 Videos

  • MAGNETIC PROPERTIES OF MATTER

    HC VERMA|Exercise Exercise|9 Videos

Similar Questions

Explore conceptually related problems

The magnetic field due to a current carrying circular coil on the axis, at a large distance r from the centre of the coil, varies approximately as ..........

An element dl = dx hat i ( where dx hat i = 1 cm) is placed at the origin and carries a large current I = 10 A. what is the magnetic field on the Y-axis at a distance of 0.5m?

Knowledge Check

  • The magnetic field due to a current carrying circular coil on the a xx is, at a large distance r from the centre of the coil, varies approximately as

    A
    `(l)/(r )`
    B
    `(l)/(r^((3)/(2)))`
    C
    `(i)/(r^(3))`
    D
    `(l)/(r^(2))`

    • Similar Questions

    Explore conceptually related problems

    An element Delta l = Delta x hat i is placed at the origin and carries a large current I= 10 A( figure). What is the magnetic field on the y - axis at a distance of 0.5 m. Delta x = 1 cm

    P(vec p) and Q(vec q) are the position vectors of two fixed points and R(vec r) is the position vectorvariable point. If R moves such that (vec r-vec p)xx(vec r -vec q)=0 then the locus of R is

    A very long bar magnet is placed with its north pole coinciding with the centre of a circular loop carrying an electric current. i . The magnetic field due to the magnet at a point on the periphery of the wire is B . The radius of the loop is a . The force on the wire is

    A particle of charge q moves with velocity vec(v) along positive y - direction in a magnetic field vec(B) . Compute the Lorentz force experienced by the particle when magnetic field is along positive y-direction

    The magnetic field existing in a region is given by vecB =B_0(1+(x)/(l))vec k. A square loop of edge l and carrying a current I, is placed with its edges parallel to the x-y axes. Find the magnitude of the net magnetic force experienced by the loop.

    A particle of charge q moves with velocity vec(v) along positive y - direction in a magnetic field vec(B) . Compute the Lorentz force experienced by the particle when magnetic field points in positive z - direction

    In Ampere's law (oint (vec B).(vec dl))=(mu_0)I , the current outside the curve is not included on the right hand side. Does it mean that the magnetic field B calculated by using Ampere's law , gives the contribution of only the currents crossing the area bounded by the curve?

    Home
    Profile