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In the electrolysis of acidulated water,...

In the electrolysis of acidulated water, it is desired to obtain 1.12 cc of hydrogen per second uner S.T.P. condition. The current to be passed is

A

9.65 A

B

19.3 A

C

0.965 A

D

1.93 A

Text Solution

Verified by Experts

The correct Answer is:
A
AT S.T.P. , 22400 c.c. of `H_(2)=1` mol of `H_(2)`
`:.1.12c.c.` of `H_(2)=(1)/(22400)xx1.12`
`=5xx10^(-5)` mol
`:.` Mass of `H_(2)` liberated, `w=2xx5xx10^(-5)`
`=10^(-4)` g
According to Faraday.s first law,
`w=Z xx I xx t`
or `w=("Equivalent wt."xxI xx t)/(96500)`
Here, `w=10^(-4)g`
Equivalent wt. of hydrogen `=1`
`I= ? " " t=1s`
`:.10^(-4)=(1)/(96500)xxIxxt`
or `I=96500xx10^(-4)`
`=9.65A`.
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Knowledge Check

  • In the electrolysis of acidulated water, it is desired to obtain 1.12 cc of Hydrogen per second under S.T.P. condition.The current ot be passed is

    A
    1.93 Amp
    B
    9.65 Amp
    C
    19.3 Amp
    D
    0.965 Amp

  • The quantity of electricity required to liberate 112 cm^(3) of hydrogen at STP from acidulated water is

    A
    965 C
    B
    1 Faraday
    C
    0.1 F
    D
    96500 C

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    `224cm^(3)`
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    `1.008g`
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