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The harmonic mean of two numbers is 4. T...

The harmonic mean of two numbers is 4. Their arithmetic mean `A` and the geometric mean `G` satisfy the relation `2A+G^2=27.` Find two numbers.

Text Solution

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Let the numbers be a and b.
Given, `H=4`
`therefore " " G^(2)=AH=4A" " "…..(i)"`
and given `2A+G^(2)=27`
`implies 2A+4A=27" " [" From Eq. (i) " ]`
`therefore A=(9)/(2)`
From Eq.(i), `G^(2)=4xx(9)/(2)=18`
Now, from important theorem of GM lt brgt `a,b=Apm sqrt(A^(2)-G^(2))=(9)/(2) pm sqrt(((81)/(4)-18))`
`=(9)/(2)pm(3)/(2)=6,3 " or " 3,6`
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Knowledge Check

  • Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the equation :

    A
    `x^(2) + 18x+ 16 = 0`
    B
    `x^(2) - 18x + 16 = 0 `
    C
    ` x^(2) + 18x - 16 = 0`
    D
    `x^(2) - 18 x - 16 = 0`
  • The H.M. of two numbers is 4 and A.M. A and G.M. G satisfy the relation 2A+G^(2) = 27 , the numbers are :

    A
    6,3
    B
    5,4
    C
    5,-25
    D
    `-3,11`
  • The geometric mean of the numbers 3, 9, 27, 81, 243 is :

    A
    `3 sqrt(3)`
    B
    81
    C
    27
    D
    9
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