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The electronic configuration of iron (26...

The electronic configuration of iron (26) is

A

2,8,14

B

2,8,12,2

C

2,8,10,4

D

2,8,14,1

Text Solution

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The correct Answer is:
To determine the electronic configuration of iron (atomic number 26), we can follow these steps: ### Step 1: Identify the Atomic Number The atomic number of iron is 26. This means that an iron atom has 26 electrons. ### Step 2: Fill the Electron Shells Electrons fill the atomic orbitals in a specific order based on the Aufbau principle, which states that electrons occupy the lowest energy orbitals first. The order of filling is as follows: 1. 1s 2. 2s 3. 2p 4. 3s 5. 3p 6. 4s 7. 3d ### Step 3: Distribute the Electrons Now, we will distribute the 26 electrons according to the order of filling: - **1s** can hold 2 electrons: 1s² (2 electrons) - **2s** can hold 2 electrons: 2s² (2 electrons) - **2p** can hold 6 electrons: 2p⁶ (6 electrons) - **3s** can hold 2 electrons: 3s² (2 electrons) - **3p** can hold 6 electrons: 3p⁶ (6 electrons) - **4s** can hold 2 electrons: 4s² (2 electrons) - **3d** can hold 10 electrons, but we only need 6 for iron: 3d⁶ (6 electrons) ### Step 4: Write the Full Electronic Configuration Combining all the filled orbitals, we get the electronic configuration of iron: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶ ### Step 5: Write the Shortened Configuration Using the nearest noble gas (argon, which has an atomic number of 18) to simplify, we can write the electronic configuration as: [Ar] 4s² 3d⁶ ### Step 6: Verify the Total Number of Electrons To ensure the configuration is correct, we can count the total number of electrons: - 1s² = 2 - 2s² = 2 - 2p⁶ = 6 - 3s² = 2 - 3p⁶ = 6 - 4s² = 2 - 3d⁶ = 6 Adding these gives us: 2 + 2 + 6 + 2 + 6 + 2 + 6 = 26, which matches the atomic number of iron. ### Final Answer The electronic configuration of iron (26) is: **[Ar] 4s² 3d⁶** or in terms of distribution: **2, 8, 14, 2**.
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Knowledge Check

  • The electronic configuration of Si is

    A
    `[Ne]3s^(2)3p^(2)`
    B
    `[Kr]4d^(10) 5s^(2)5p^(2)`
    C
    `[He]2s^(2)2p^(2)`
    D
    `[Ar]3d^(10)4s^(2)4p^(2)`
  • The electronic configuration of B is

    A
    `1s^(2) 2s^(2) 2p^(1)`
    B
    `1s^(2) 2s^(2) 2p^(2)`
    C
    `1s^(2) 2s^(2) 2p^(3)`
    D
    `1s^(2) 2s^(2) 2p^(4)`
  • The electronic configuration of Cr is

    A
    2, 8, 13, 1
    B
    2, 8, 14
    C
    2, 8, 12, 2
    D
    2, 8, 10,4
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