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Equivalent weight of KMnO4 in acidic me...

Equivalent weight of `KMnO_4` in acidic medium is

A

M/2

B

M/4

C

M/7

D

M/5

Text Solution

Verified by Experts

The correct Answer is:
D
M/5
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Equivalent weights of KMnO_(4) in acidic medium, alkaline medium and neutral (dilute alkaline) medium respectively are M/5, M/1 , M/3 . Reduced products can be :

STATEMENT-1: The equivalent mass of of KMnO_(4) in acidic medium is (M)/(5) where M=molecular mass of KMnO_(4) STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.

Knowledge Check

  • STATEMENT-1 KMnO_(4) acts as powerful oxidising agent in acids, alkaline and neutral medium. STATEMENT-2: Equivalent weight of KMnO_(4) in acidic medium in M/5 and in strongly alkaline medium in M/3. STATEMENT-3 : KMnO_(4) solution is used as a primary standard and acts as self indicator during its titration more Mohr salt.

    A
    T F T
    B
    F T T
    C
    F F T
    D
    F F F

  • The equivalent weight of KNnO_4 in acidic medium would be

    A
    `158.0`
    B
    `79.0`
    C
    52.7
    D
    31.6

  • The equivalent weight of MnO_(4)^(-) ion in acidic medium is

    A
    `31.6`
    B
    `23.8`
    C
    55
    D
    119

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    (a) Why do transition elements show catalytic properties? (b) Calculate equivalent weight of KMnO_4 in neutral medium. ( c) What is the cause of lanthanoid contraction?

    What is the equivalent weight of KMNO_(4) in: Neutral medium

    STATEMENT-1 KMnO_(4) overset("acidic medium")to Mn^(2+) , n factor of KMnO_(4) is 5 and STATEMENT-2 Equivalent mass of KMnO_(4) in acidic medium is (M)/(5) (M=molecular mass of KMnO_(4) )

    If the molecular weight of Ba(MnO_(4))_(2) is M , then the equivalent weight of Ba(MnO_(4))_(2) in acidic medium is

    Equivalent weight of MnO_(4)^(-) in acidic, weakly basic and neutral medium are in the ratio of

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