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Equivalent weight of KMnO4 in acidic me...

Equivalent weight of `KMnO_4` in acidic medium is

A

M/2

B

M/4

C

M/7

D

M/5

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The correct Answer is:
D
M/5
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STATEMENT-1 KMnO_(4) acts as powerful oxidising agent in acids, alkaline and neutral medium. STATEMENT-2: Equivalent weight of KMnO_(4) in acidic medium in M/5 and in strongly alkaline medium in M/3. STATEMENT-3 : KMnO_(4) solution is used as a primary standard and acts as self indicator during its titration more Mohr salt.

Equivalent weights of KMnO_(4) in acidic medium, alkaline medium and neutral (dilute alkaline) medium respectively are M/5, M/1 , M/3 . Reduced products can be :

The equivalent weight of MnO_(4)^(-) ion in acidic medium is

STATEMENT-1 KMnO_(4) overset("acidic medium")to Mn^(2+) , n factor of KMnO_(4) is 5 and STATEMENT-2 Equivalent mass of KMnO_(4) in acidic medium is (M)/(5) (M=molecular mass of KMnO_(4) )

If the molecular weight of Ba(MnO_(4))_(2) is M , then the equivalent weight of Ba(MnO_(4))_(2) in acidic medium is

STATEMENT-1: The equivalent mass of of KMnO_(4) in acidic medium is (M)/(5) where M=molecular mass of KMnO_(4) STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.

(a) Why do transition elements show catalytic properties? (b) Calculate equivalent weight of KMnO_4 in neutral medium. ( c) What is the cause of lanthanoid contraction?

ARIHANT PUBLICATION JHARKHAND-CONCEPT OF ATOMIC MOLECULAR AND EQUIVALENT MASSES-EXAM BOOSTER FOR CRACKING EXAM
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