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At the start of a motion along a line th...

At the start of a motion along a line the initial velocity is u and acceleration is at. The final velocity vafter time t, is

A

`v= u + at`

B

`v = u + at^(2)`

C

`v = u +(1)/(2) at^(2)`

D

`v = at^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the final velocity \( v \) after time \( t \) given the initial velocity \( u \) and acceleration \( a \), we can follow these steps: ### Step 1: Understand the relationship between acceleration, velocity, and time. Acceleration \( a \) is defined as the rate of change of velocity with respect to time. Mathematically, this is expressed as: \[ a = \frac{dv}{dt} \] ### Step 2: Rearrange the equation for integration. To find the change in velocity, we can rearrange the equation: \[ dv = a \, dt \] ### Step 3: Integrate both sides. We will integrate both sides to find the relationship between velocity and time. The left-hand side will be integrated with respect to \( v \) and the right-hand side with respect to \( t \): \[ \int dv = \int a \, dt \] ### Step 4: Set the limits of integration. The limits for the left-hand side (velocity) will be from the initial velocity \( u \) to the final velocity \( v \), and for the right-hand side (time), from \( 0 \) to \( t \): \[ \int_{u}^{v} dv = \int_{0}^{t} a \, dt \] ### Step 5: Solve the integrals. The left-hand side gives: \[ v - u \] The right-hand side, assuming \( a \) is constant, gives: \[ at \] ### Step 6: Combine the results. Now we can combine the results from both sides: \[ v - u = at \] ### Step 7: Solve for final velocity \( v \). Rearranging the equation gives us: \[ v = u + at \] ### Conclusion: The final velocity \( v \) after time \( t \) is: \[ v = u + at \]

To find the final velocity \( v \) after time \( t \) given the initial velocity \( u \) and acceleration \( a \), we can follow these steps: ### Step 1: Understand the relationship between acceleration, velocity, and time. Acceleration \( a \) is defined as the rate of change of velocity with respect to time. Mathematically, this is expressed as: \[ a = \frac{dv}{dt} \] ...
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Knowledge Check

  • At the start of a motion along a line the initial velocity is u and acceleration is at. The final velocity v after time t, is

    A
    `v=u+at`
    B
    `v=u+at^(2)`
    C
    `v=u+(1)/(2)at^(2)`
    D
    `v=at^(2)`
  • At the start of a motion along a line the initial velocity is u and acceleration is at. The final velocity v after timet, is

    A
    v = u + at
    B
    `v = u + a t^(2)`
    C
    `v = u + (1)/(2) a t^(2)`
    D
    `v = a t^(2)`
  • A particle of mass m is moving along the line y-b with constant acceleration a. The areal velocity of the position vector of the particle at time t is (u=0)

    A
    constant
    B
    `(abt)/(2)`
    C
    `(abt)/(2m)`
    D
    `(a^(2)bt)/(2m)`
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