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A body is projected upwards under gravit...

A body is projected upwards under gravity with a speed of 19.6 Then, maximum height which can be reached is

A

4.9 m

B

19.6 m

C

9.8 m

D

39.2 m

Text Solution

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The correct Answer is:
To solve the problem of finding the maximum height reached by a body projected upwards with an initial speed of 19.6 m/s under the influence of gravity, we can use the following steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Initial velocity (u) = 19.6 m/s - Final velocity (v) at maximum height = 0 m/s (since the body stops rising at the maximum height) - Acceleration due to gravity (g) = 9.8 m/s² (acting downwards) 2. **Use the Kinematic Equation:** We will use the third equation of motion: \[ v^2 = u^2 - 2gh \] where: - \(v\) = final velocity - \(u\) = initial velocity - \(g\) = acceleration due to gravity - \(h\) = maximum height 3. **Substitute the Known Values:** Since \(v = 0\) at maximum height, we can substitute the values into the equation: \[ 0 = (19.6)^2 - 2 \cdot 9.8 \cdot h \] 4. **Rearranging the Equation:** Rearranging the equation to solve for \(h\): \[ 2 \cdot 9.8 \cdot h = (19.6)^2 \] \[ h = \frac{(19.6)^2}{2 \cdot 9.8} \] 5. **Calculate \(h\):** First, calculate \( (19.6)^2 \): \[ (19.6)^2 = 384.16 \] Now substitute this value into the equation: \[ h = \frac{384.16}{2 \cdot 9.8} \] \[ h = \frac{384.16}{19.6} = 19.6 \text{ m} \] 6. **Conclusion:** The maximum height \(h\) that the body can reach is **19.6 meters**.

To solve the problem of finding the maximum height reached by a body projected upwards with an initial speed of 19.6 m/s under the influence of gravity, we can use the following steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Initial velocity (u) = 19.6 m/s - Final velocity (v) at maximum height = 0 m/s (since the body stops rising at the maximum height) - Acceleration due to gravity (g) = 9.8 m/s² (acting downwards) ...
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Knowledge Check

  • A cricket ball is thrown up with a speed of 19.6 m/s. The maximum height it can reach is (take g= 9.8 m/ s^2 )

    A
    `9.8m`
    B
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    C
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    D
    same velocity at 2T
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