A person of 60 kg enters a lift going up with an acceleration `2 ms^(- 2)` The vertical upward force acting on the person will be `(g = 10 ms ^(-2))`

Options

A. 600 N
B. 720N
C. 620N
D. 1200 N

Explanation

To find the vertical upward force acting on a person in a lift that is accelerating upwards, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Mass of the person, \( m = 60 \, \text{kg} \)
- Acceleration of the lift, \( a = 2 \, \text{m/s}^2 \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)

2. **Understand the Forces Acting on the Person:**
- The person experiences two forces:
- The gravitational force acting downwards, which is the weight of the person: \( W = mg \)
- The normal force acting upwards, which we need to calculate and denote as \( N \).

3. **Write the Equation of Motion:**
- When the lift accelerates upwards, the net force acting on the person can be expressed using Newton's second law:
\[ F_{\text{net}} = m \cdot a \]
- The net force can also be expressed as the difference between the normal force and the weight:
\[ F_{\text{net}} = N - mg \]

4. **Set Up the Equation:**
- Combining the two expressions for net force, we have:
\[ N - mg = m \cdot a \]
- Rearranging gives:
\[ N = mg + ma \]

5. **Substitute the Values:**
- Now, substitute the values of \( m \), \( g \), and \( a \):
\[ N = (60 \, \text{kg} \times 10 \, \text{m/s}^2) + (60 \, \text{kg} \times 2 \, \text{m/s}^2) \]
- Calculate each term:
\[ N = 600 \, \text{N} + 120 \, \text{N} \]
- Therefore:
\[ N = 720 \, \text{N} \]

6. **Conclusion:**
- The vertical upward force acting on the person is \( 720 \, \text{N} \).