A body of 1 quintal moves with a constant velocity of 1000 m/s on a horizontal frictionless path. The force acting on the body is

Options

A. zero
B. `100 xx 1000 N `
C. 1000 N
D. 100 N

Explanation

To solve the problem, we need to determine the force acting on a body that is moving with a constant velocity. Here are the steps to arrive at the solution:

### Step 1: Understand the given information
The problem states that a body of mass 1 quintal is moving with a constant velocity of 1000 m/s on a horizontal frictionless path.

### Step 2: Convert the mass into standard units
1 quintal is equivalent to 100 kg (since 1 quintal = 100 kg).

### Step 3: Identify the formula for force
According to Newton's second law of motion, the force acting on an object is given by:
\[ F = m \cdot a \]
where:
- \( F \) is the force,
- \( m \) is the mass of the body,
- \( a \) is the acceleration of the body.

### Step 4: Determine the acceleration
Since the body is moving with a constant velocity, the acceleration \( a \) is zero. This is because acceleration is defined as the rate of change of velocity with respect to time:
\[ a = \frac{dv}{dt} \]
Since the velocity is constant (1000 m/s), there is no change in velocity, hence:
\[ a = 0 \]

### Step 5: Calculate the force
Now, substituting the values into the force equation:
\[ F = m \cdot a = 100 \, \text{kg} \cdot 0 \, \text{m/s}^2 = 0 \, \text{N} \]

### Conclusion
The force acting on the body is **0 N**.