The edge length of a unit cell is 408 pm . Its density is `10.6 g cm^(-3)`. Predict whether the metal is body cenetred , or simple cubic .
Molar mass of the metal ` = 107.9 g mol^(-1)` and `N_(A) = 6.023 xx 10^(23)`.

Explanation

Given, a = 408 pm = `408 xx 10^(-10) cm `
`rho = 10.6 g cm^(-3) ,M = 107.9 , N_(A) =6.023 xx 10^(23)`
Applying the formula,
` Z = (a^(3) xx rho xx N_(A))/(M)`
` = ((408 xx 10^(-10))^(3) xx 10.6 xx 6.023 xx 10^(23))/(107.9)`
= 4
Valume of Z indicaties that the metal has fcc strcture .