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The third viral coefficient for real gas...

The third viral coefficient for real gas is `2 xx 10^(-2) ("L mole"^(-1))`. The molar volume of gas at `27^@`C and 5 atm Pressure may be-

A

5.12 L

B

5.00 L

C

5.18 L

D

5.06 L

Text Solution

Verified by Experts

The correct Answer is:
D

Viral expansion is
`Z = 1 + B/V_(infty) + c/V_(m^(2)) +`……
`C = b^(2) = 2 xx 10^(-2) ("L moles"^(-1))^(2)`
`b = sqrt(2) xx 10^(-1) = 1.44 = 0.1414 "L mole"^(-1)`
`V_("ideal") = (nRT)/P = (0.082 xx 300)/5 24.6/5`
`V_("real") = V_("ideal") + nb`
`= 4.92 + 1(0.1414)`
`= 4.9200`
`=0.1414 + 5.0614 = 5.06` L
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Knowledge Check

  • The third virial coefficient of a real gas 2xx10^(-2) (L//"mol")^(2) . The value of van der Waals' constant 'b' is:

    A
    0.1414 L/mol
    B
    0.707 L/mol
    C
    0.2828 L/mol
    D
    none of these
  • The third virial coefficient of He gas is 4xx10^(-2)(L//"mol")^(2) , then what will be volume of 2 mole He gas at 1 atm and 273 K?

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    22.0L
    B
    44.0L
    C
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    D
    45.2L
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    22.4 litres
    B
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    C
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    D
    5.6 litres
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