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In a 0.2 m aqueous solution of week acid...

In a `0.2 m` aqueous solution of week acid, HX, the degree of ionization is `0.3.` Taking `K _(f)` for water as
`1 85 K kg "mole" ^(-1),` the freezing point of the solution will be nearest to :

A

`- 0. 360 ^(@)C`

B

`- 0. 260^(@)C`

C

`+ .480^(@)C`

D

`272.52 K`

Text Solution

Verified by Experts

The correct Answer is:
D
Initially with 1 mol,
` {:(HX " "to " "H ^(+) " "+ " "X ^(-)), ( ( 1- 0. 3) " "0.3 " "0.3):}`
Total number of moles of all species =1. 3
so, `I = 1. 3` ( Van.t Hoff factor)
`( - Delta T _(f) ) = iK _(f). m`
`= 1. 3 xx 1. 85 xx 0. 2 = 0. 48 K`
`T_(f) = 273 - 0 . 48 = 272 . 52 K`
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Knowledge Check

  • In a 0.2 molal aqueous solution of a week acid HX, the degree of ionisation is 0.3. Taking K_(F) for water as 1.85, the freezing point of the solution will be nearest to

    A
    `-0.360^(@)C`
    B
    `-0.260^(@)C`
    C
    `+0.480^(@)C`
    D
    `-0.481^(@)C`

  • In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3. Taking K_(f) for water as 1.85, the freezing point of the solution will be nearest to

    A
    `-0.480^(@)C`
    B
    `-0.360^(@)C`
    C
    `-0.260^(@)C`
    D
    `+0.480^(@)C`

  • In a 0.2 molal aqueous solution of a weak acid HX the degree of ionisation is 0.3. Taking K, for water as 1.85^@C m^(-1) , the freezing point of solution will be nearest to

    A
    `- 0.480^@C`
    B
    `-0.360^@C`
    C
    `-0.260^@C`
    D
    `+ 0.480^@C`

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