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Number of moles of MnO(4)^(-) is require...

Number of moles of `MnO_(4)^(-)` is required to oxidize one mole of ferrous oxalate completely in an acidic medium will be

A

0.4 moles.

B

7.5 moles

C

0.2 moles

D

0.6 moles

Text Solution

Verified by Experts

The correct Answer is:
D
`[Fe(C_(2)O_(4))toFe^(3+)+2CO_(2)+3e^(-)]xx5` (oxidation)
`[MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(2+)+4H_(2)O]` (Reduction) `xx3`
5 moles `Fe(C_(2)O_(4))-=3` moles `KMnO_(4)`
1 moles `Fe(C_(2)O_(4))-=0.6` moles `KMnO_(4)`
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Knowledge Check

  • Number of moles of MnO_(4)^(-) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

    A
    7.5 moles
    B
    0.2 moles
    C
    0.6 moles
    D
    0.4 moles

  • Number of moles of MnO_(4)^(-) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

    A
    7.5 moles
    B
    0.2 moles
    C
    0.6 moles
    D
    0.4 moles

  • Number of moles of MnO_(4)^(-) required to oxidise one mole of ferrous oxalate completely in acidic medium will be

    A
    0.6 mole
    B
    0.4 mole
    C
    7.5 mole
    D
    0.2 mole

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