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Cr^(2+) and Mn^(3+) both have d^(4) co...

`Cr^(2+)` and `Mn^(3+)` both have `d^(4)` configuration. Thus

A

both are reducing agents.

B

both are oxidizing agents.

C

`Cr^(2+)` is an oxidizing agent while `Mn^(3+)` is a reducing agent.

D

`Mn^(3+)` is an oxidizing agent while `Cr^(2+)` is a reducing agent.

Text Solution

Verified by Experts

The correct Answer is:
D

Extra stability is gained when `Mn^(3+)` is reduced to `Mn^(2+)` and is thus an oxidizing agent.
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Knowledge Check

  • Assertion : Cr^(2+) is reducing and Mn^(3+) is oxidising. Reason : Cr^(2+) and Mn^(3+) have d^4 configuration.

    A
    If both assertion and reason are true and reason is the correct explanation of assertion.
    B
    If both assertion and reason are true and reason not is the correct explanation of assertion.
    C
    If assertion is trun but reason is false.
    D
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  • The ion Cr^(2+) is redusing agent while that of Mn^(3+) is an oxidising agent though both have 3d^(4) configuration. This is because

    A
    `Cr^(2+)` configuration results from `d^(3) to d^(4)` while that of `Mn^(3+)` result from highly stable `d^(5)` configuration
    B
    `Cr^(2+)` Configuration results from `d^(4) to d^(3)` while that of `Mn^(3+)` results from highly stable `d^(5)` configuration.
    C
    Both the ions, `Cr^(2+)` and `Mn^(3+)` results from `d^(5)` configuration.
    D
    `Cr^(2+)` configuration results from `d^(5)` while that of Mn results from `d^(5)`

  • Which of the following statement are correct about Cr^(2+) (Z = 24) and Mn^(3+) (Z = 25) ? (i) Cr^(2+) is a reducing agent (ii) Mn^(3+) is an oxidizing agent (iii) Both Cr^(2+) and Mn^(3+) exhibit d^(4) configuration (iv) When Cr^(2+) is used as a reducing agent, the chromium ion attains d^(5) electronic configuration

    A
    (i), (ii), (iii), (iv)
    B
    (ii), (iii), (iv)
    C
    (i), (ii), (iii)
    D
    (ii), (iii)

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