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Find the number of radial nodes in 3p or...

Find the number of radial nodes in 3p orbital.

Text Solution

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For 3p-orbital, n=3 and `l=1`, therefore, number of radial nodes `=(n-l-1)=(3-1-1)=1`.
Number of angular nodes `=(l)=1` and Total number of nodes `=(n-I) =(3-1)=2`
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Knowledge Check

  • Assertion : 2p orbitals do not have any spherical node. Reason : The number of nodes in p-orbitals is given by (n-2) where n is the principal quantum number.

    A
    If both (A) and (R) are correct and (R) is the correct explanation of(A).
    B
    If both (A) and (R) are correçt, but (R) is not the correct explanation of (A).
    C
    If (A) is correct, but (R) is incorrect.
    D
    If both (A) and (R) are incorrect.

  • The number of radial nodes of '3 s' and '2 p' -orbitals are respectively:

    A
    2,0
    B
    0,2
    C
    1,2
    D
    2,1

  • For an atom or ion having single electron, compare the energies of the following orbitals: S_(1)= a spherically symmetrical orbital having two spherical nodes. S_(2) = an orbital which is double dumb-bell and has no radial node. S_(3) = an orbital with orbital angular momentum zero and three radial nodes. S_(4) = an orbital having one planar and one radial node.

    A
    `S_(1)=S_(2)=S_(3)=S_(4)`
    B
    `S_(1)=S_(2)=S_(4) lt S_(3)`
    C
    `S_(1) gt S_(2) gt S_(3) gt S_(4)`
    D
    `S_(1) lt S_(4) lt S_(3) lt S_(2)`

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    Assertion : In nth normal inode of a stretched string, there are n antinodes and (n+1) nodes. . Reason : The ends of string are nodes, so the number of node is one more than the number of antinodes.

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