Home
Class 11
CHEMISTRY
For an electron in a hydrogen atom, the ...

For an electron in a hydrogen atom, the wave function y is proportional to exp-`r//a_(0)`, where `a_(0)` is the Bohr radius. Find the ratio of probability of finding the electron at the nucleus to the probability of finding it at `a_(0)`.

Text Solution

Verified by Experts

Probability of finding the electron at `s=a_(0)` is proportional to `e^(-2s//a_(0)=e^(-2)`
Since `P= |Psi|^(2) prop (e ^(-s//a_(0)))^(2)`, probability at nucleus = 0
Promotional Banner

Similar Questions

Explore conceptually related problems

For an electron in a hydrogen atom, the wave function psi is proportional to exp -r//a_(0) , where a_(0) is the Bohr radius. Find the ratio of probability of finding the electron at the nucleus to the probability of finding it at a_(0) .

Represent graphically, the variation of probability density (psi^2 _(r)) as a function of distance (r ) of the electron from the nucleus for 1s and 2s orbitals.

The Schrodinger wave equation for hydrogen atom is psi _(2r)^(2)=0=[(1)/(4 sqrt(2 pi))]^(2) (2-(r_(0))/(a_(0)))e^(-r_(n)//a_(0)) where a_(0) is Bohr's radius. Let the radial node be at r_(0) then find r in terms of a_(0) .

A (6, 0) is a point on a circle with center (0, 0).Find the radius of the circle.

A random variable X has the following probability distribution: find P(0 lt X lt 3)