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Two identical wires A and B have the sam...

Two identical wires A and B have the same length L and carry the same current I. Wire A is bent into a circle of radius R and wire B is bent to form a square of side a. If `B_1 and B_2` are the values of magnetic induction at the centre of the square respectively, then the ratio is `B_1/B_2` is

A

`((pi^2)/(8))`

B

`((pi^2)/(8sqrt2))`

C

`((pi^2)/(16))`

D

`((pi^2)/(16sqrt2))`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Two identical wires A and B have the same length l and carry the same current I. Wire A is bent into a circle of radius R and wire B is bent to form a square of side a. If B_1 and B_2 are the values of magnetic induction at the centre of the circle and the centre of the square, respectively, then the ratio B_1//B_2 is

    A
    `(pi^2//8)`
    B
    `(pi^2//8sqrt2)`
    C
    `(pi^2//16)`
    D
    `(pi^2//16sqrt2)`

  • Two identical wires A and B , each of length 'l', carry the same current I . Wire A is bent into a circle of radius R and wire B is bent to form a square of side 'a' . If B_(A) and B_(B) are the values of magnetic field at the centres of the circle and square respectively , then the ratio (B_(A))/(B_(B)) is :

    A
    `( pi^(2))/(16)`
    B
    ` (pi^(2))/(8 sqrt(2))`
    C
    ( pi^(2))/(8)`
    D
    `(pi^(2))/(16 sqrt(2))`

  • A wire in the form of a square of side '2m' carries a current 2A . Then the magentic induction at the centre of the square wire is ( magnetic permeability of free space =mu_(0))

    A
    `(mu_(0))/(2pi)`
    B
    `(mu_(0)sqrt(2))/(pi)`
    C
    `(2sqrt(2)mu_(0))/(pi)`
    D
    `(mu_(0))/(sqrt(2pi))`

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