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Estimate the energy released in the fusi...

Estimate the energy released in the fusion reaction:
`""_(1)^(2)H + ""_(2)^(3)He to ""_(2)^(4)He + ""_(1)^(1)H`
Given atomic masses : `""^(2)H = 2.041 u`
`""^(3)He = 3.0160 u, ""^(4)He = 4.0026 u, ""^(1)H = 1.0078 u`

Text Solution

Verified by Experts

Mass defect `Deltam` = (mass of `""^(2)H` + mass of `""^(3)He`) -( mass of `""^(4)He` + mass of `""^(1)H`)
`=2.0141 u + 3.0160 u - 4.0026 u - 1.0078`
`u=0.00197 u`
`E = Deltam (u) xx 931.4 = 0.197 u xx 931.4 = 18.35 MeV`.
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