Complete the following reaction :
` CH_3COONa + NaOH overset( CaO) to `

Options

A. ` CH_3COONa + NaOH overset(CaO) to NaOH`
B. ` CH_3COONa + NaOH overset(CaO) to CH_3COOH+ Ca(OH)_2`
C. ` CH_3COONa + NaOH overset(CaO) to CH_4+Na_2CO_3`
D. ` CH_3COONa + NaOH overset(CaO) to CH_3COOCa+ NaOH`

Explanation

To complete the reaction of sodium acetate (CH₃COONa) with sodium hydroxide (NaOH) in the presence of calcium oxide (CaO), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are sodium acetate (CH₃COONa) and sodium hydroxide (NaOH), along with calcium oxide (CaO) which acts as a dehydrating agent.

2. **Understand the Reaction Type**:
This reaction is a decarboxylation reaction, which occurs when a carboxylic acid salt is heated with a strong base and a dehydrating agent. In this case, we are using soda-lime (a mixture of NaOH and CaO).

3. **Write the Reaction**:
The sodium salt of acetic acid (sodium acetate) reacts with sodium hydroxide and calcium oxide. The decarboxylation process will lead to the formation of methane (CH₄) and sodium carbonate (Na₂CO₃).

The balanced reaction can be written as:
\[ \text{CH}_3\text{COONa} + \text{NaOH} + \text{CaO} \rightarrow \text{CH}_4 + \text{Na}_2\text{CO}_3 \]

4. **Identify the Products**:
The products of this reaction are methane (CH₄) and sodium carbonate (Na₂CO₃).

5. **Final Equation**:
Thus, the complete reaction is:
\[ \text{CH}_3\text{COONa} + \text{NaOH} + \text{CaO} \rightarrow \text{CH}_4 + \text{Na}_2\text{CO}_3 \]