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In the following question, A statement o...

In the following question, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.
Assertion (A): If the median and mode of a frequency distribution are 150 and 154 respectively. Then its mean is 148.
Reason (R): Mean, median and mode of a frequency distribution are related as 3Mean=3Median - Mode.

A

Both A and R are true and R is the correct explanation for A.

B

Both A and R are true and R is not correct explanation for A.

C

A is true but R is false.

D

A is false but R is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given assertion and reason statements regarding the relationship between mean, median, and mode in a frequency distribution. ### Step-by-Step Solution: 1. **Understand the Assertion (A)**: - The assertion states that if the median is 150 and the mode is 154, then the mean is 148. 2. **Understand the Reason (R)**: - The reason states that the relationship between mean, median, and mode is given by the formula: \[ 3 \times \text{Mean} = 3 \times \text{Median} - \text{Mode} \] 3. **Check the Given Formula**: - The correct relationship is: \[ \text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean} \] - However, the reason provided in the question is incorrect. 4. **Use the Correct Formula**: - Rearranging the correct formula gives us: \[ 2 \times \text{Mean} = 3 \times \text{Median} - \text{Mode} \] - This can be rewritten as: \[ \text{Mean} = \frac{3 \times \text{Median} - \text{Mode}}{2} \] 5. **Substitute the Values**: - Substitute the given values of median and mode into the formula: - Median = 150 - Mode = 154 - Plugging in these values: \[ \text{Mean} = \frac{3 \times 150 - 154}{2} \] 6. **Calculate the Mean**: - Calculate \(3 \times 150\): \[ 3 \times 150 = 450 \] - Now substitute this back into the equation: \[ \text{Mean} = \frac{450 - 154}{2} \] - Calculate \(450 - 154\): \[ 450 - 154 = 296 \] - Now divide by 2: \[ \text{Mean} = \frac{296}{2} = 148 \] 7. **Conclusion**: - The calculated mean is indeed 148, which confirms the assertion is correct. - However, the reason provided is incorrect because the formula stated is not the standard relationship between mean, median, and mode. ### Final Answer: - The assertion (A) is true, and the reason (R) is false. Therefore, the correct choice is that the assertion is correct, but the reason is incorrect.
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Knowledge Check

  • The median and mode of a frequency distribution are 26 and 29 respectively. Then , the mean is

    A
    27.5
    B
    24.5
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    28.4
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    25.8
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    B
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    41
    D
    40
  • Relation between mean, median and mode -

    A
    `barX = M = Z`
    B
    `barX gt M gt Z`
    C
    `barX lt M lt Z`
    D
    None of these
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