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An ideal gas undergoes a reversible isot...

An ideal gas undergoes a reversible isothermal expansion from state I to state II followed by a reversible adiabatic expansion from state II to state III. The correct plot(s) representing the changes from state I to state III is(are)

A

B

C

D

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The correct Answer is:
To solve the problem of an ideal gas undergoing a reversible isothermal expansion followed by a reversible adiabatic expansion, we need to analyze the processes step by step and determine the correct plots that represent the changes from state I to state III. ### Step 1: Understand the Processes 1. **Reversible Isothermal Expansion (State I to State II)**: - In this process, the temperature remains constant (T = constant). - As the gas expands, its volume increases (V increases). - Since the process is isothermal for an ideal gas, the pressure decreases (P decreases) according to the ideal gas law (PV = nRT). 2. **Reversible Adiabatic Expansion (State II to State III)**: - In this process, there is no heat exchange with the surroundings (Q = 0). - The gas does work on the surroundings as it expands, which results in a decrease in internal energy (U decreases). - Consequently, the temperature of the gas decreases (T decreases) during this expansion. ### Step 2: Analyze the Graphs 1. **Graph A (P vs. V)**: - For the isothermal process (I to II), the curve is hyperbolic, showing a decrease in pressure with an increase in volume. - For the adiabatic process (II to III), the curve is steeper than the isothermal curve, indicating a more significant decrease in pressure with volume increase. - This graph is correct. 2. **Graph B (P vs. T)**: - From I to II, since the temperature is constant, the line is horizontal. - From II to III, as the gas expands adiabatically, the temperature decreases, resulting in a downward slope. - This graph is also correct. 3. **Graph C (H vs. S)**: - For the isothermal process, enthalpy (H) remains constant, but the entropy (S) increases. - For the adiabatic process, the temperature decreases, which should lead to a decrease in enthalpy as well. - If the graph shows an increase in enthalpy while the temperature is decreasing, this is incorrect. 4. **Graph D (T vs. S)**: - During the isothermal expansion, the temperature remains constant, leading to a horizontal line. - During the adiabatic expansion, the temperature decreases while entropy increases. - This graph is correct. ### Conclusion The correct plots representing the changes from state I to state III are: - **Graph A (P vs. V)** - **Graph B (P vs. T)** - **Graph D (T vs. S)** **Incorrect Plot**: - **Graph C (H vs. S)** is incorrect due to the inconsistency in the expected behavior of enthalpy during the adiabatic process. ### Final Answer: The correct plots are A, B, and D. The incorrect plot is C.
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Knowledge Check

  • In a change from state A to state B

    A
    `q` depends only on the initial and final state
    B
    `w` depends only on the initial and final state
    C
    `DeltaE` depends only on the initial and final state
    D
    `DeltaE` depends upon the path adopted by `A` to change into `B`.
  • In a change from state A to state B:

    A
    "q" depends only on the initial and final state.
    B
    W depends only on the initial and final state.
    C
    `DeltaE` depends only on the initial and final state,
    D
    `DeltaE` depends upon the path adopted by "A" to change into "B"
  • An ideal gas undergoes isothermal process from some initial state i to final state f. Choose the correct alternative

    A
    `dU=0`
    B
    `"d"theta=0`
    C
    `"d"theta=dU`
    D
    `dw=dw`
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