Equal weights of methane and oxygen are mixed in a vessel. The partial pressure of oxygen is

Options

A. `1//3`
B. `2//3`
C. `(1)/(2)`
D. `(1)/(2) xx (273)/(298)`

Answer

A

Explanation

Molecular weight of methane
`(CH_(4)) = 12 + 4 = 16`
Molecular weight of oxygen `(O_(2)) = 32`
Let the weight of methane
= Weight of `O _(2) = Mg`
Number of moles of methane =M/32
Number of moles of `O _(2) = (M)/( 32)`
Total number of moles `= ( M )/(16) + (M)/(32) = (3M )/(32)`
Hence, partial pressure of `O _(2)`
` = ((M )/(32))/(( 3M )/(32)) xx p = (1)/(3) xx p`