In the reaction
`BrCH_2 - CH_2 Br + Zn to Y + ZnBr_2 `, Y is

Options

A. ethyne
B. ethene
C. ethane
D. None of these

Explanation

To solve the question regarding the reaction of `BrCH2-CH2Br` with `Zn` to produce `Y` and `ZnBr2`, we can follow these steps:

### Step 1: Identify the Reactants
The reactant given is `BrCH2-CH2Br`, which is known as 1,2-dibromoethane. This compound has two bromine atoms attached to the two carbon atoms of an ethane chain.

**Hint:** Look for the structure of the compound to understand how the bromine atoms are positioned.

### Step 2: Understand the Reaction with Zinc
When 1,2-dibromoethane reacts with zinc, a reduction reaction occurs. Zinc acts as a reducing agent and facilitates the elimination of bromine atoms.

**Hint:** Remember that zinc can help in the elimination of halogens in organic compounds.

### Step 3: Determine the Product
In the elimination reaction, the two bromine atoms are removed, leading to the formation of a double bond between the two carbon atoms. This results in the formation of ethene (C2H4).

**Hint:** Consider what happens when two halogens are removed from a molecule; typically, a double bond is formed.

### Step 4: Write the Balanced Reaction
The balanced reaction can be represented as follows:
\[ \text{BrCH}_2-\text{CH}_2\text{Br} + \text{Zn} \rightarrow \text{C}_2\text{H}_4 + \text{ZnBr}_2 \]

Here, `C2H4` is ethene, which is our product `Y`.

**Hint:** Ensure that the number of atoms on both sides of the reaction is equal to confirm the reaction is balanced.

### Conclusion
Thus, the product `Y` in the reaction is ethene (C2H4).

**Final Answer:** Y is ethene (C2H4).

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