Acetic acid reacts with NaOH to produce a salt, whose pH is

Options

A. less than 7
B. equal to 7
C. more than 7
D. equal to 14

Explanation

To solve the question regarding the pH of the salt produced when acetic acid reacts with sodium hydroxide (NaOH), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Acetic acid (CH₃COOH) is a weak acid.
- Sodium hydroxide (NaOH) is a strong base.

2. **Write the Reaction**:
- The reaction between acetic acid and sodium hydroxide can be represented as:
\[ \text{CH}_3\text{COOH} + \text{NaOH} \rightarrow \text{CH}_3\text{COONa} + \text{H}_2\text{O} \]
- Here, sodium acetate (CH₃COONa) is formed as the salt.

3. **Determine the Nature of the Salt**:
- Sodium acetate is the salt produced from the neutralization of a weak acid (acetic acid) and a strong base (sodium hydroxide).
- Salts formed from weak acids and strong bases tend to be basic in nature.

4. **Analyze the pH of the Salt Solution**:
- When sodium acetate dissolves in water, it can hydrolyze to produce hydroxide ions (OH⁻), which makes the solution basic.
- The reaction can be represented as:
\[ \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^- \]
- The presence of hydroxide ions indicates that the pH of the solution will be greater than 7.

5. **Conclusion**:
- Therefore, the pH of the solution containing sodium acetate will be more than 7.

### Final Answer:
The pH of the salt (sodium acetate) produced from the reaction of acetic acid with NaOH is **more than 7** (Option C).