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3.4 g of CaCl2 is dissolved in 2.5 L of ...

3.4 g of `CaCl_2` is dissolved in 2.5 L of water at 300 K. What is the osmotic pressure of the solution? van't Hoff factor for `CaCl_2` is 2.47.

Text Solution

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`pi = iMRT = i(W_2RT)/(M_2V)`
i = 2.47, `W_2` = 3.4 g, R = 0.08206 `dm^3`atm `K^(-1)` `mol^(-1)`, T= 300 K, `M_2` = 40+71=111 g `mol^(-1), V = 2.5 dm^3`
`pi =2.47xx (3.4 cancel(g)xx 0.08206 cancel(dm^3) atm cancel(K^(-1))cancel(mol^(-1)) cx 300 K)/(111 cancel(g)cancel(mol^(-1))xx 2.5 cancel(dm^3))`
= 0.745 atm
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