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In Fig.2, a quadrilateral ABCD is drawn ...

In Fig.2, a quadrilateral ABCD is drawn to circumscribe a circle, with centre O, in such a way that the sides AB, BC, CD and DA touch the circle at the points P, Q, R and S respectively. Prove that AB + CD = BC + DA.

Answer

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Knowledge Check

  • A quadrilateral ABCD is drawn to circumscribe a circle such that its sides. AB , BC ,CD and DA touch the circle at P,Q,R and S , respectively . If AB = x cm BC = 7 cm , CR = 3 cm and AS = 5 cm , then x= ?

    A
    10 cm
    B
    8 cm
    C
    9 cm
    D
    7 cm

  • Quadrilateral ABCD is circumscribed to a circle. If AB=6cm , BC=7cm and CD=4cm then the length of AD is

    A
    `3cm`
    B
    `4cm`
    C
    `6cm`
    D
    `7cm`

  • A quadrilateral ABCD circumscribes a circle and AB = 6 cm, CD = 5 cm and AD = 7 cm. The length of side BC is

    A
    4 cm
    B
    5 cm
    C
    3 cm
    D
    6 cm

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    In figure, a quadrilateral ABCD is drawn to circumscribe a circle such that its sides AB, BC, CD and AD touch the circle at P, Q, R and S respectively. If AB = x cm, BC = 7 cm, CR = 3cm and AS = 5cm, then x = ______.

    A circle with centre P is inscribed in the Delta ABC Side AB, side BC and side A C touch the circle at points L,M and N respectively . Prove that : A (DeltaABC ) = 1/2 (AB +BC + AC) xxr

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    A quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB+CD=AD+BC. or A circle touches all the four sides of a quadrilateral ABCD. Prove that AB+CD=BC+DA.

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