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The area of a triangle with vertices (a,...

The area of a triangle with vertices (a,b+c), (b,c+a) and (c,a+b) is

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If a+b+c=lambda, then circumcentre of the triangle with vertices (a,b,c);(b,c,a) and (c,a,b) is

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Knowledge Check

  • The area of the triangle with vertices at (a, b+c), (b, c+a) and (c, a+b) is

    A
    `0`
    B
    a-b-c
    C
    ab+bc+ca
    D
    a+b+c
  • If the area of the triangle whose vertices are (b, c), (c, a) and (a, b) is Delta , then the area of triangle whose vertices are (ac - b^2, ab -c^2), (ba-c^2, bc-a^2) and (cb-a^2, ca - b^2) , is

    A
    `Delta^2`
    B
    `(a+b+c)^2 Delta`
    C
    `a Delta+b Delta^2`
    D
    None of these
  • The area of triangle having vertices A(a,b+c) B(a,b,-c) and C(-a,c) where (a,b,c > 0 ) , is

    A
    ac
    B
    2ac
    C
    3ac
    D
    4ac
  • Similar Questions

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