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Ifx(1),x(2),x(3),"……" are in A.P., then ...

If`x_(1),x_(2),x_(3),"……"` are in A.P., then the value of `1/(x_(1)x_(2))+1/(x_(2)x_(3))+1/(x_(3)x_(4))+"……"1/(x_(n-1)x_(n))` is :

A

`(n-1)/(x_(1)x_(n))`

B

`(n-1)/(x_(2)x_(n-1))`

C

`n/(x_(1)x_(n))`

D

`(n+1)/(x_(1)x_(n))`

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