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A particle of mass m strikes elastically...

A particle of mass m strikes elastically against a wall at angle of incidence `60^@` with velocity v. The change in momentum is

A

mv

B

2mv

C

`(mv)/2`

D

`(mv)/4`

Text Solution

Verified by Experts

The correct Answer is:
A
Change in momentum=Final momentum-Initial momentum
= `mv cos 60^@ -(-mv cos 60^2)`
` =2mv cos 60^@`
`=2mv(1)/2 = mv`
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