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A particle of mass m strikes elastically...

A particle of mass m strikes elastically against a wall at angle of incidence `60^@` with velocity v. The change in momentum is

A

mv

B

2mv

C

`(mv)/2`

D

`(mv)/4`

Text Solution

Verified by Experts

The correct Answer is:
A
Change in momentum=Final momentum-Initial momentum
= `mv cos 60^@ -(-mv cos 60^2)`
` =2mv cos 60^@`
`=2mv(1)/2 = mv`
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Knowledge Check

  • A particle of mass M strikes a wall at an angle of incidence 60^(@) with velocity V elastically Then the change in momentum is

    A
    `(MV)/2`
    B
    `MV`
    C
    `-2MV`
    D
    zero

  • In kinetic theory of gases, a molecule of mass m of an ideal gas collides with a wall of vessel with velocity v. The change in the linear momentum of the molecule is

    A
    2mv
    B
    mv
    C
    -mv
    D
    zero

  • A particle of mass, strikes on ground with angle of incidence 45^(@) , what will be the velocity after reflection if coefficient of restitution e=1/(sqrt(2))

    A
    `(sqrt(2)v)/3`
    B
    `v/(sqrt(3))`
    C
    `v/2`
    D
    `(sqrt(3)v)/2`

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