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If domain of f(x) is [1, 3], then find t...

If domain of f(x) is [1, 3], then find the domain off `f (log_(2) (x^(2) + 3x -2 ))`

A

`[ -5 ,-4 ] cup [ 1,2]`

B

`[ -13 , -2] cup [ (3)/(2), 5]`

C

`[ - 4,1] cup [ 2,7]`

D

`[3,2]`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If domain of f(x) is [1, 3], then the domain of f(log_(2)(x^(2)+3x-2)) is

    A
    `[-5,-4]uu[1,2]`
    B
    `[-13,-2]uu[(3)/(5),5]`
    C
    `[4,1]uu[2,7]`
    D
    `[-3,2]`

  • The domain of f(x) = (log_(2) (x+3))/(x^(2) + 3x +2) , is

    A
    `R-{-1, - 2 }`
    B
    `(-2, oo)`
    C
    `R-{-1, -2, - 3}`
    D
    `(-3, oo)-{-1, -2}`

  • The domain of f(x)=(log_(2)(x+3))/(x^(2)+3x+2) is

    A
    `R-{-1,-2}`
    B
    `(-2,oo)`
    C
    `R-{-1,-2,-3}`
    D
    `(-3,oo)-{-1,-2}`

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