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In a coil of self-inductance 10mH, the c...

In a coil of self-inductance 10mH, the current I (in ampere) varies with time t (in second) as i=8t+2amp

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Knowledge Check

  • In an inductor of self-inductance L=2 mH, current changes with time according to relation i=t^(2)e^(-t) . At what time emf is zero ?

    A
    4s
    B
    3s
    C
    2s
    D
    1s

  • In an inductor of self-inductance L=2 mH, current changes with time according to relation i=t^(2)e^(-t) . At what time emf is zero ?

    A
    4s
    B
    3s
    C
    2s
    D
    1s

  • Two different coils have self-inductances L_(1) = 8 mH and L_(2) = 2 mH . The current in one coil is increased at a constant rate. The current in the second coil is also increased at the same constant rate. At a certain instant of time, the power given to the two coil is the same. At that time, the current, the induced voltage and the energy stored in the first coil are i_(1), V_(1) and W_(1) respectively. Corresponding values for the second coil at the same instant are i_(2), V_(2) and W_(2) respectively. Then:

    A
    `(W_(2))/(W_(1))=8`
    B
    `(W_(2))/(W_(1))=(1)/(8)`
    C
    `(W_(2))/(W_(1))=4`
    D
    `(W_(2))/(W_(1))=(1)/(4)`

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