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Assertion (A) Cr^(2+) is reducing while ...

Assertion (A) `Cr^(2+)` is reducing while `Mn^(3+)` is oxidising when both have `d^4`configuration.
Reason ( R) Configuration of `Cr^2+` changes from `d^3` to `d^4`

A

Both Assertion and Reason are correct explanation of the Assertion

B

Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

C

Assertion is correct but Reason is incorrect

D

Both Assertion and Reason are incorrect

Text Solution

Verified by Experts

The correct Answer is:
C
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Why is Cr^(2+) reducing and Mn^(3+) oxidising when both have d^(4) configuration ?

Why is Cr^(3+) reducing and Mn^(3+) oxidisin when both have d^(4) configuration ?

Knowledge Check

  • Assertion : Cr^(2+) is reducing and Mn^(3+) is oxidising. Reason : Cr^(2+) and Mn^(3+) have d^4 configuration.

    A
    If both assertion and reason are true and reason is the correct explanation of assertion.
    B
    If both assertion and reason are true and reason not is the correct explanation of assertion.
    C
    If assertion is trun but reason is false.
    D
    If both assertion and reason are false.

  • Assertion :- Cr^(+2) is a reducing agent and Mn^(+3) is oxidising agent. Reason :- Mn^(+3) has d^(5) configuration.

    A
    If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
    B
    If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
    C
    If Assertion is True but the Reason is False.
    D
    If both Assertion & Reason are False.

  • The ion Cr^(2+) is redusing agent while that of Mn^(3+) is an oxidising agent though both have 3d^(4) configuration. This is because

    A
    `Cr^(2+)` configuration results from `d^(3) to d^(4)` while that of `Mn^(3+)` result from highly stable `d^(5)` configuration
    B
    `Cr^(2+)` Configuration results from `d^(4) to d^(3)` while that of `Mn^(3+)` results from highly stable `d^(5)` configuration.
    C
    Both the ions, `Cr^(2+)` and `Mn^(3+)` results from `d^(5)` configuration.
    D
    `Cr^(2+)` configuration results from `d^(5)` while that of Mn results from `d^(5)`

    • Similar Questions

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    (a) What happens when (i) Manganate ions (MnO_(4)^(2-)) undergoes diSQProportionation reaction in acidic medium ? (ii) Lanthanum is heated with Sulphur? (b) Explain the following trends in the properties of the members of the First series of transition elements: (i) E^(@) (M^(2+)//M) value for copper is positive (+ 0.34 V) in contrast to the other members of the series. (ii) Cr^(2+) is reducing while Mn^(3+) is oxidising, though both have d^(4) configuration. (iii) The oxidising power in the series increases in the order VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt MnO_94)^(-) .

    Cr^(2+) and Mn^(3+) both have d^(4) configuration. Thus

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    The Cu^(2) having 3d^(9) congiguration, Cu^(+) having 3d^(10) configuration. The Cu^(2+) is ,

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