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Show that 12^n cannot end with the digit...

Show that `12^n` cannot end with the digits `0` or `5` for any natural number `n`

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Assertion (A): 6^(n) ends with the digit zero where n is a natural number. Reason (R):Any number ends with digit zero, if its prime factor is of the form 2^(m)xx5^(n) , where m,n are natural numbers.