The temperature coefficient of resistance of wire is `0.001259^(@)C^(-1)`. If resistance is `1Omega` at 300 K, then `2Omega` will be at:

Options

A. 1400 K
B. 1100 K
C. 1127 J
D. 1154 K

Explanation

To solve the problem, we need to find the temperature at which the resistance of the wire becomes 2 Ohms, given that the resistance is 1 Ohm at 300 K and the temperature coefficient of resistance is \( \alpha = 0.001259 \, ^\circ C^{-1} \).

### Step-by-Step Solution:

1. **Understanding the relationship between resistance and temperature**:
The resistance of a material changes with temperature according to the formula:
\[ R_T = R_0 (1 + \alpha (T - T_0)) \]
where:
- \( R_T \) is the resistance at temperature \( T \),
- \( R_0 \) is the resistance at reference temperature \( T_0 \),
- \( \alpha \) is the temperature coefficient of resistance,
- \( T \) is the temperature in Kelvin,
- \( T_0 \) is the reference temperature in Kelvin.

2. **Substituting known values**:
We know:
- \( R_0 = 1 \, \Omega \) at \( T_0 = 300 \, K \),
- \( R_T = 2 \, \Omega \).

Plugging these values into the formula gives:
\[ 2 = 1 (1 + 0.001259 (T - 300)) \]

3. **Simplifying the equation**:
This simplifies to:
\[ 2 = 1 + 0.001259 (T - 300) \]
Subtracting 1 from both sides:
\[ 1 = 0.001259 (T - 300) \]

4. **Isolating \( T \)**:
Dividing both sides by \( 0.001259 \):
\[ T - 300 = \frac{1}{0.001259} \]
Now calculate \( \frac{1}{0.001259} \):
\[ T - 300 \approx 794.3 \]

5. **Calculating \( T \)**:
Adding 300 to both sides:
\[ T \approx 794.3 + 300 = 1094.3 \, K \]

6. **Final answer**:
Rounding to the nearest whole number, we find:
\[ T \approx 1094 \, K \]

### Conclusion:
Thus, the temperature at which the resistance of the wire becomes 2 Ohms is approximately **1094 K**.