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Find out vecE at x = 4 if the potential ...

Find out `vecE` at x = 4 if the potential at a point x due to some charges situated on x-axis is `v_((x))=(20)/((x^2-4))V:`

A

`9/10V//mum`

B

`18/12V//mum`

C

`80/120V//mum`

D

`10/9V//mum`

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Knowledge Check

  • The potential at a point x ( measured in mu m) due to some charges situated on the x-axis is given by V(x)=20//(x^2-4) vol t

    A
    (a) `(10//9) vol t//mu m` and in the `+ve` x direction
    B
    (b) `(5//3)vol t//mu m` and in the `-ve` x direction
    C
    (c) `(5//3) vol t//mu m` and in the `+ve` x direction
    D
    (d) `(10//9) vol t//mu m` and in the `-ve` x direction

  • The potential at a point distant x (mesured in mum ) due to some charges situated on the x-axis is given by V (x)=(20)/(x^(2)-4) V. The electric field at x=4 mum is given by

    A
    `5/3 Vmu m^(-1)` and in positive x direction
    B
    `10/9 V mu m^(-1)` and in negative x direction
    C
    `10/9V mu m^(-1)` and in positive x direction
    D
    `5/3 V mu m^(-1)` and in negative x direction.

  • The electric potential at a point (x,y,z) is given by V=-s^(2)

    A
    `vecE=hati(2xy -z^(3))+hatj xy^(2)+hatk 3 z^(2)x `
    B
    `vecE=hati(2xy +z^(3))+hatj x^(2)+hatk 3 xz^(2) `
    C
    `vecE=hati 2xy + hatj (x^(2)+y^(2))+hatk(3xz-y^(2))`
    D
    `vecE=hatiz + hatj xyz+ hatkz^(2)`

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