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The linear mass density 'mu' of the stri...

The linear mass density `'mu'` of the string is (where, mass of the string = m, length of the string = L)

A

`m/L`

B

mL

C

`mt^2`

D

`m/L_3`

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A
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The linear mass density of the string shown in the figure is mu = 1 g//m . One end (A) of the string is tied to a prong of a tuning fork and the other end carries a block of mass M. The length of the string between the tuning fork and the pulley is L = 2.0 m . When the tuning fork vibrates, the string resonates with it when mass M is either 16 kg or 25 kg. However, standing waves are not observed for any other value of M lying between 16 kg and 25 kg. Assume that end A of the string is practically at rest and calculate the frequency of the fork.

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Knowledge Check

  • The linear mass density mu of the string is (where, mass of the string = m, length, of the string g = L)

    A
    `m/L`
    B
    mL
    C
    `mL^2`
    D
    `m/L_3`

  • The mass suspended from the stretched string of a sonometer is 4 kg and the linear mass density of string 4 xx 10^(-3) kg m^(-1) . If the length of the vibrating string is 100 cm , arrange the following steps in a sequential order to find the frequency of the tuning fork used for the experiment . (A) The fundamental frequency of the vibratinng string is , n = (1)/(2l) sqrt((T)/(m)) . (B) Get the value of length of the string (l) , and linear mass density (m) of the string from the data in the problem . (C) Calculate the tension in the string using , T = mg . (D) Substitute the appropriate values in n = (1)/(2l) sqrt((T)/(m)) and find the value of 'n' .

    A
    BCAD
    B
    ABCD
    C
    DCBA
    D
    BADC

  • Four pieces of string of length L are joined end to end to make a long string of length 4L. The linear mass density of the strings are mu,4mu,9mu and 16mu , respectively. One end of the combined string is tied to a fixed support and a transverse wave has been generated at the other end having frequency f (ignore any reflection and absorption). string has been stretched under a tension F . Find the time taken by wave to reach from source end to fixed end.

    A
    `(25)/(12)xx(L)/sqrt(F//mu)`
    B
    `(10L)/sqrt(F//mu)`
    C
    `(4L)/sqrt(F//mu)`
    D
    `(L)/sqrt(F//mu)`

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