The geometry of `H_2S` and its dipole moment are:

Options

A. Angular and non-zero
B. Angular and zero
C. Linear and zero
D. Linear and non-zero

Explanation

To determine the geometry of \( H_2S \) (hydrogen sulfide) and its dipole moment, we can follow these steps:

### Step 1: Identify the central atom
The central atom in \( H_2S \) is sulfur (S).

**Hint**: Look for the atom that is bonded to the other atoms in the molecule.

### Step 2: Determine the valence electrons
Sulfur is in group 16 of the periodic table and has 6 valence electrons. Each hydrogen (H) atom contributes 1 valence electron. Therefore, the total number of valence electrons in \( H_2S \) is:
\[ 6 \text{ (from S)} + 1 \times 2 \text{ (from 2 H)} = 8 \text{ valence electrons} \]

**Hint**: Count the valence electrons from each atom based on their group number in the periodic table.

### Step 3: Determine the hybridization
To find the hybridization, we can use the formula:
\[ \text{Hybridization} = \frac{\text{Number of valence electrons}}{2} + \text{Number of lone pairs} \]
In \( H_2S \), sulfur has 2 lone pairs (since it has 6 valence electrons and forms 2 bonds with hydrogen). Thus:
\[ \text{Hybridization} = \frac{8}{2} = 4 \text{ (which corresponds to sp}^3\text{ hybridization)} \]

**Hint**: Remember that each bond and lone pair counts towards the total number of regions of electron density.

### Step 4: Determine the molecular geometry
With \( sp^3 \) hybridization, the ideal geometry is tetrahedral. However, due to the presence of 2 lone pairs, the shape of the molecule is bent or angular.

**Hint**: Visualize the arrangement of bonds and lone pairs to determine the actual shape.

### Step 5: Analyze the dipole moment
In \( H_2S \), sulfur is more electronegative than hydrogen. The bond dipoles from the S-H bonds will not cancel out due to the bent shape of the molecule, resulting in a net dipole moment.

**Hint**: Consider the electronegativity of the atoms and the geometry when determining if the dipoles cancel.

### Conclusion
The geometry of \( H_2S \) is angular, and it has a non-zero dipole moment due to the asymmetrical distribution of charge.

**Final Answer**: The geometry of \( H_2S \) is angular and its dipole moment is non-zero.