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A piece of wire 22 cm long is bent into ...

A piece of wire 22 cm long is bent into the form of an arc of a circle subtending an angle of `60^(@)` at its centre. Find the radius of the circle. `["Use" pi = (22)/(7)]`

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To solve the problem step by step, we will follow the mathematical approach outlined in the video transcript. ### Step-by-Step Solution 1. **Identify the Given Information:** - Length of the wire (arc length) = 22 cm - Central angle (θ) = 60 degrees - We will use π = 22/7. 2. **Convert the Angle from Degrees to Radians:** - We know that \( 180^\circ \) is equivalent to \( \pi \) radians. - To convert \( 60^\circ \) to radians, we can use the conversion factor: \[ \text{Radians} = \text{Degrees} \times \frac{\pi}{180} \] - Thus, \[ 60^\circ = 60 \times \frac{\pi}{180} = \frac{\pi}{3} \text{ radians} \] 3. **Use the Formula for Arc Length:** - The formula for the length of an arc (L) is given by: \[ L = r \times \theta \] - Here, \( L = 22 \) cm and \( \theta = \frac{\pi}{3} \). 4. **Substitute the Values into the Formula:** - We can rearrange the formula to solve for the radius (r): \[ r = \frac{L}{\theta} \] - Substituting the known values: \[ r = \frac{22}{\frac{\pi}{3}} = 22 \times \frac{3}{\pi} \] 5. **Substitute the Value of π:** - Now, substituting \( \pi = \frac{22}{7} \): \[ r = 22 \times \frac{3}{\frac{22}{7}} = 22 \times \frac{3 \times 7}{22} \] 6. **Simplify the Expression:** - The \( 22 \) in the numerator and denominator cancels out: \[ r = 3 \times 7 = 21 \text{ cm} \] ### Final Answer: The radius of the circle is **21 cm**.
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Knowledge Check

  • If the piece of wire 25 cm long is bent into an arc of a circle subtending an angle of 75^(@) at the centre , then the radius of the circle ( in cm ) is :

    A
    `(pi)/(120)`
    B
    `(60)/(pi)`
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    `60 pi `
    D
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    `pi/120`
    B
    `60/pi`
    C
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    D
    none of these
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    `(2M//pi)`
    B
    `(M//pi)`
    C
    `(3sqrt(3)M//pi)`
    D
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